Comments on: AS3 Character Movement: Following Mouse with Easing

By: Dallas

Dallas — Fri, 11 Jun 2010 10:10:17 +0000

I managed to fudge something together.

The previous tutorial used code that would only allow the Hero to travel at the maximum speed. This tutorial calculates movement based off of the speed(sort of like using the speed as an acceleration). That’s the key.

——
if (Math.sqrt(yDistance*yDistance + xDistance*xDistance) < (speed*speed))
{
x -= (x – stageRef.mouseX) / (speed);
y -= (y – stageRef.mouseY) / (speed);
}
else
{
x += Math.cos(radian) * speed;
y += Math.sin(radian) * speed;
}
——

The ‘if’ statement executes the easing statements once the the distance between the mouse and the Hero is equal to the speed*speed, giving you a comfortable amount of room to slow down.

The ‘else’ statement executes the original movement statement (which used speed as the maximum speed) whenever the Hero is too far away from the mouse to begin easing.

What you have left is an object that will move at a maximum speed until it reaches a point to start easing gently to a rest at your mouse position.

Hope I got this right.

By: John

John — Sat, 20 Mar 2010 19:23:12 +0000

Whats a good way to add a max speed with easing? I tried:
if (xMovement > maxSpeed) {
xMovement = maxSpeed;
}
if (xMovement < -maxSpeed) {
xMovement = -maxSpeed;
}
I did the same thing with y… it didn’t seem to work right.

By: Andrew

Andrew — Sun, 25 Oct 2009 22:00:25 +0000

Nice tut!

By: Dennis

Dennis — Thu, 27 Aug 2009 10:37:09 +0000

I’d like to be able to embed te AS into the swf. Not set the AS class as linkage for the MC. Please help. Thanks

By: AS3 Object Oriented Custom Cursor | AS Gamer | Making Flash Games

AS3 Object Oriented Custom Cursor | AS Gamer | Making Flash Games — Tue, 24 Mar 2009 20:11:14 +0000

[...] Stephent: Just noticed that (Math.sqrt(yDistance*yDistance + xDistance*xDistance) < speed) should be… [...]

By: Par

Par — Fri, 20 Mar 2009 13:09:12 +0000

LOL as far as the comment looks… you’ve wrote the same thing twice. But I think I know what you are talking about, I’ll fix it.

By: Stephent

Stephent — Fri, 20 Mar 2009 13:05:35 +0000

Just noticed that (Math.sqrt(yDistance*yDistance + xDistance*xDistance) < speed) should be

(Math.sqrt(yDistance*yDistance + xDistance*xDistance) < speed).

ST.